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mysql5.7以下怎麽解析json

DELIMITER $$

USE `dw`$$

DROP FUNCTION IF EXISTS `fn_Json_getKeyValue`$$

CREATE DEFINER=`data`@`%` FUNCTION `fn_Json_getKeyValue`(

in_JsonArray VARCHAR(4096),#JSON數組字符串

in_Index TINYINT, #JSON對象序號,序號從1開始

in_KeyName VARCHAR(64)#鍵名

) RETURNS VARCHAR(512) CHARSET utf8

BEGIN

DECLARE vs_return VARCHAR(4096);

DECLARE vs_JsonArray, vs_Json, vs_KeyName VARCHAR(4096);

#declare vs_Json varchar(4096);

DECLARE vi_pos1, vi_pos2 SMALLINT UNSIGNED;

#寫監控日誌

#insert into dw.t_etl_log(sp_name, title, description)

#values('dw.fn_Json_getKeyValue', '通過Json鍵名取鍵值', concat('in_JsonArray=', in_JsonArray));

SET vs_JsonArray = TRIM(in_JsonArray);

SET vs_KeyName = TRIM(in_KeyName);

IF vs_JsonArray = '' OR vs_JsonArray IS NULL

OR vs_KeyName = '' OR vs_KeyName IS NULL

OR in_Index <= 0 OR in_Index IS NULL THEN

SET vs_return = NULL;

ELSE

#去掉方括號

SET vs_JsonArray = REPLACE(REPLACE(vs_JsonArray, '[', ''), ']', '');

#取指定的JSON對象

SET vs_json = SUBSTRING_INDEX(SUBSTRING_INDEX(vs_JsonArray,'}', in_index),'}',-1);

IF vs_json = '' OR vs_json IS NULL THEN

SET vs_return = NULL;

ELSE

SET vs_KeyName = CONCAT('"', vs_KeyName, '":');

SET vi_pos1 = INSTR(vs_json, vs_KeyName);

IF vi_pos1 > 0 THEN

#如果鍵名存在

SET vi_pos1 = vi_pos1 + CHAR_LENGTH(vs_KeyName);

SET vi_pos2 = LOCATE(',', vs_json, vi_pos1);

IF vi_pos2 = 0 THEN

#最後壹個元素沒有','分隔符,也沒有結束符'}'

SET vi_pos2 = CHAR_LENGTH(vs_json) + 1;

END IF;

SET vs_return = REPLACE(MID(vs_json, vi_pos1, vi_pos2 - vi_pos1), '"', '');

END IF;

END IF;

END IF;

RETURN(vs_return);

END$$

DELIMITER ;

測試: {"old_current_score":"2","new_current_score":"0","old_grade_id":"1","new_grade_id":"1","grade_time":"2016-04-09 00:43:26","grade_upgrade_time":"2017-04-09 00:43:26"}

select fn_Json_getKeyValue(reason,1,'old_grade_id');